$conn = mysqli_connect("数据库主机名", "用户名", "密码", "数据库名"); if (!$conn) { die("数据库连接失败:" . mysqli_connect_error()); }
$.ajax({ url: "test.php", type: "POST", data: { name: "John", location: "Boston" } }) .done(function( msg ) { alert( "数据已发送: " + msg ); }) .fail(function() { alert( "请求发送失败" ); });
$name = $_POST['name'];
$location = $_POST['location'];
echo "姓名:" . $name . "
城市:" . $location;
$("#myDiv").load("test.php", { name: "John", location: "Boston" });