可以使用以下代码示例来解决此问题:
import json
import boto3
def lambda_handler(event, context):
glue = boto3.client('glue')
# 获取所有数据库
databases = glue.get_databases()
for database in databases['DatabaseList']:
# 获取每个数据库中的所有表
tables = glue.get_tables(DatabaseName=database['Name'])
for table in tables['TableList']:
# 判断表是否为空
partition_keys = table.get('PartitionKeys')
if partition_keys and len(partition_keys) == 1 and partition_keys[0]['Name'] == 'year':
# 获取表路径并删除表
table_uri = table['StorageDescriptor']['Location']
glue.delete_table(DatabaseName=database['Name'], Name=table['Name'])
# 重新创建空表
empty_table = {
"Name": table['Name'],
"StorageDescriptor": {
"Columns": [
{
"Name": "Col1",
"Type": "string",
"Comment": ""
}
],
"Location": table_uri,
"InputFormat": "org.apache.hadoop.mapred.TextInputFormat",
"OutputFormat": "org.apache.hadoop.hive.ql.io.HiveIgnoreKeyTextOutputFormat",
"Compressed": False,
"NumberOfBuckets": -1,
"SerdeInfo": {
"SerializationLibrary": "org.apache.hadoop.hive.serde2.lazy.LazySimpleSerDe",
"Parameters": {
"serialization.format": "1"
}
}
},
"PartitionKeys": [
{
"Name": "year",
"Type": "string"
}
],
"TableType": "EXTERNAL_TABLE",
"Parameters": {
"classification": "parquet",
"transient_lastDdlTime": str(int(time.time()))
}
}
# 创建新的空表
glue.create_table(
DatabaseName=database['Name'],
TableInput=empty_table
)
这段代码使用AWS Lambda和AWS Glue API来检查所有数据库中的所有表,并删除为空的表。然后,它重新创建空表,该表只包含一个列“Col1”。这可以防止AWS Glue爬虫在读取空文件时创建多个表。
上一篇:AWSGlue爬虫问题
下一篇:AWSGluePyspark:java.lang.NoClassDefFoundError:org/jets3t/service/ServiceException