在Android中创建zip文件可以使用Java的ZipOutputStream类。下面是一个示例代码：

import android.util.Log;

import java.io.BufferedInputStream;
import java.io.BufferedOutputStream;
import java.io.File;
import java.io.FileInputStream;
import java.io.FileOutputStream;
import java.io.IOException;
import java.util.zip.ZipEntry;
import java.util.zip.ZipOutputStream;

public class ZipUtils {

    private static final int BUFFER_SIZE = 1024;

    public static void createZipFile(String sourceFolderPath, String zipFilePath) throws IOException {
        FileOutputStream fos = new FileOutputStream(zipFilePath);
        ZipOutputStream zos = new ZipOutputStream(new BufferedOutputStream(fos));

        File sourceFolder = new File(sourceFolderPath);
        addFilesToZip(sourceFolder, sourceFolder.getName(), zos);

        zos.close();
    }

    private static void addFilesToZip(File file, String parentPath, ZipOutputStream zos) throws IOException {
        byte[] buffer = new byte[BUFFER_SIZE];

        if (file.isDirectory()) {
            File[] files = file.listFiles();
            for (File childFile : files) {
                addFilesToZip(childFile, parentPath + "/" + file.getName(), zos);
            }
        } else {
            FileInputStream fis = new FileInputStream(file);
            BufferedInputStream bis = new BufferedInputStream(fis, BUFFER_SIZE);

            String zipEntryPath = parentPath + "/" + file.getName();
            ZipEntry zipEntry = new ZipEntry(zipEntryPath);
            zos.putNextEntry(zipEntry);

            int count;
            while ((count = bis.read(buffer, 0, BUFFER_SIZE)) != -1) {
                zos.write(buffer, 0, count);
            }

            bis.close();
        }
    }
}

使用上述代码，你可以调用createZipFile()方法来创建一个包含指定文件夹内容的zip文件。需要传入源文件夹路径和目标zip文件路径作为参数。