要解决这个问题，我们可以使用字典来存储每个部门的员工信息和工资。首先，我们需要一个包含员工详细信息的员工列表。每个员工的详细信息可以用包含姓名、部门和工资的字典表示。

然后，我们可以遍历员工列表，并将每个员工的工资累加到对应部门的工资总和中。我们还可以使用字典的嵌套结构，将每个部门的员工信息存储在一个字典中。

下面是一个示例代码：

employees = [
    {"name": "John", "department": "HR", "salary": 5000},
    {"name": "Alice", "department": "IT", "salary": 6000},
    {"name": "Bob", "department": "HR", "salary": 4000},
    {"name": "Jane", "department": "IT", "salary": 5500}
]

department_salaries = {}  # 存储按部门划分的工资总和和员工信息的字典

for employee in employees:
    # 获取员工的部门和工资
    department = employee["department"]
    salary = employee["salary"]
    
    # 累加工资到部门的工资总和中
    if department in department_salaries:
        department_salaries[department]["total_salary"] += salary
        department_salaries[department]["employees"].append(employee)
    else:
        department_salaries[department] = {"total_salary": salary, "employees": [employee]}

# 打印每个部门的工资总和和员工信息
for department, info in department_salaries.items():
    print("Department:", department)
    print("Total Salary:", info["total_salary"])
    print("Employees:")
    for employee in info["employees"]:
        print(employee["name"], employee["salary"])
    print()

执行以上代码将输出：

Department: HR
Total Salary: 9000
Employees:
John 5000
Bob 4000

Department: IT
Total Salary: 11500
Employees:
Alice 6000
Jane 5500

这样，我们就成功地按部门划分了员工的工资总和，并且获得了每个员工的详细信息。