1. 通过遍历循环对比列表

list1 = [1, 2, 3, 4]
list2 = [2, 4, 6, 8, 10]

for i in range(min(len(list1), len(list2))):
    if list1[i] == list2[i]:
        print("Match found at index", i)
    else:
        print("No match found at index", i)

2. 使用zip函数将列表打包成元组进行比较

list1 = [1, 2, 3, 4]
list2 = [2, 4, 6, 8, 10]

for i, (a, b) in enumerate(zip(list1, list2)):
    if a == b:
        print("Match found at index", i)
    else:
        print("No match found at index", i)

3. 使用numpy库中的array_equal()函数比较两个数组是否相等

import numpy as np

list1 = [1, 2, 3, 4]
list2 = [2, 4, 6, 8, 10]

array1 = np.array(list1)
array2 = np.array(list2[:len(list1)])

if np.array_equal(array1, array2):
    print("Arrays are equal.")
else:
    print("Arrays are not equal.")