以下是C++代码示例,用于测量互斥锁和自旋锁之间的唤醒延迟时间。
#include
constexpr int LOOP_COUNT = 10000;
std::mutex mtx;
std::atomic
void mutexWorker() { for(int i = 0; i < LOOP_COUNT; ++i) { std::unique_lockstd::mutex lock(mtx); flag = true; lock.unlock(); } }
void spinLockWorker() { for(int i = 0; i < LOOP_COUNT; ++i) { while(flag.exchange(false, std::memory_order_acquire) == false) {} } }
int main() { auto mutexStart = std::chrono::high_resolution_clock::now(); std::thread t1(mutexWorker); std::thread t2(mutexWorker); t1.join(); t2.join(); auto mutexEnd = std::chrono::high_resolution_clock::now();
auto spinLockStart = std::chrono::high_resolution_clock::now();
std::thread t3(spinLockWorker);
std::thread t4(spinLockWorker);
t3.join();
t4.join();
auto spinLockEnd = std::chrono::high_resolution_clock::now();
std::cout << "Mutex time: " << std::chrono::duration_cast(mutexEnd - mutexStart).count() / (2 * LOOP_COUNT) << " nanoseconds" << std::endl;
std::cout << "Spin lock time: " << std::chrono::duration_cast(spinLockEnd - spinLockStart).count() / (2 * LOOP_COUNT) << " nanoseconds" << std::endl;
return 0;
}
该代码使用了两个线程(t1和t2)来测试互斥锁的唤醒延迟时间,并使用了两个线程(t3和t4)测试自旋锁的唤醒
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