本问题可以通过编写C语言代码来解决。代码示例如下：

#include #include

void initialize_matrices(int rows, int cols, double A[rows][cols], double B[cols][rows]) { int i, j; for (i = 0; i < rows; i++) { for (j = 0; j < cols; j++) { A[i][j] = i + j; B[j][i] = i + j; } } }

void matrix_multiply(int rows, int cols, int size, double A[rows][cols], double B[cols][rows], double C[rows][rows]) { int i, j, k; double sum; for (i = 0; i < size; i++) { for (j = 0; j < size; j++) { sum = 0.0; for (k = 0; k < size; k++) { sum += A[i][k] * B[k][j]; } C[i][j] = sum; } } }

int main() { int sizes[] = {100, 250, 500, 750, 1000}; // Different matrix sizes to test int num_sizes = sizeof(sizes) / sizeof(int); int i, j, k, size; double A[sizes[num_sizes-1]][sizes[num_sizes-1]]; double B[sizes[num_sizes-1]][sizes[num_sizes-1]]; double C[sizes[num_sizes-1]][sizes[num_sizes-1]]; clock_t start, end; double elapsed_time;

for (k = 0; k < num_sizes; k++) {
    size = sizes[k];
    initialize_matrices(size, size, A, B);
    start = clock();
    matrix_multiply(size, size, size, A, B, C);
    end = clock();
    elapsed_time = ((double) (end - start)) / CLOCKS_PER_SEC;
    printf("Size %dx%d: %.6f seconds\n", size, size, elapsed_time);
}